| Solution If the system is in
  balance, then the two objects are stationary or both move with a constant
  velocity with the same speed. The problem can be solved using Newton’s Laws of
  Motion: 
   The problem can be solved using the principle of
  conservation of energy:     Gravitational
  potential energy   Assume that the object on the incline moves up a distance
  5 m with a constant velocity, hence the vertically hanging mass must move
  vertically down a distance of 5 m with the same speed at any instant. The
  gain in gravitational potential energy by the object on the incline must be
  equal to the gravitation potential energy lost by the hanging object. So, the
  hanging object falls 5 m while the object on the incline must rise a distance
  of 3 m. Therefore, the mass of the hanging object is 3/5 times the mass of
  the object on the incline (3/5 kg). More formally:        
  Gain in gravitational potential energy of system A            
  Loss in gravitational potential energy of system B                        Stevinus found a brilliant or
  clever way to solve this problem. Did you think of it as well? His solution
  appears on his epitaph. 
 Simon Stevin (Dutch: 1548–1620), sometimes called Stevinus, was a Dutch-Flemish mathematician, physicist
  and military engineer. He was active in a great many areas of science and
  engineering, both theoretical and practical. He also translated various
  mathematical terms into Dutch, making it one of the few European languages in
  which the word for mathematics, wiskunde (wis and kunde, i.e., "the
  knowledge of what is certain"), was not a loanword from Greek but a
  calque via Latin.      |