Solution
If the system is in
balance, then the two objects are stationary or both move with a constant
velocity with the same speed.
The problem can be solved using Newton’s Laws of
Motion:
The problem can be solved using the principle of
conservation of energy:
Gravitational
potential energy
Assume that the object on the incline moves up a distance
5 m with a constant velocity, hence the vertically hanging mass must move
vertically down a distance of 5 m with the same speed at any instant. The
gain in gravitational potential energy by the object on the incline must be
equal to the gravitation potential energy lost by the hanging object. So, the
hanging object falls 5 m while the object on the incline must rise a distance
of 3 m. Therefore, the mass of the hanging object is 3/5 times the mass of
the object on the incline (3/5 kg).
More formally:
Gain in gravitational potential energy of system A
Loss in gravitational potential energy of system B
Stevinus found a brilliant or
clever way to solve this problem. Did you think of it as well? His solution
appears on his epitaph.
Simon Stevin (Dutch: 1548–1620), sometimes called Stevinus, was a Dutch-Flemish mathematician, physicist
and military engineer. He was active in a great many areas of science and
engineering, both theoretical and practical. He also translated various
mathematical terms into Dutch, making it one of the few European languages in
which the word for mathematics, wiskunde (wis and kunde, i.e., "the
knowledge of what is certain"), was not a loanword from Greek but a
calque via Latin.
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