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VISUAL PHYSICS ONLINE 3.1
WAVES P31 002 The figures
show a standing wave in the same section of string at two different times.
There are nodes at the end of the string of length 1.00 m: x = 0 m, y =
0 mm and at x = 1.00 m, y = 0 mm.
What is the
amplitude of vibration? What is the
greatest possible period of the wave? What is the
lowest possible frequency of the standing wave? What is the
wavelength of the standing wave? What is the
speed of the transverse wave along the string? What harmonic
is vibrating in the string?
Sketch the string for this mode of vibration. What is the fundamental frequency
for the string? Sketch the string for this mode of vibration. View solution below only after you have completed the answering the question. |
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Solution Amplitude There is an antinode at position x = 0.25 m. In a time of 0.025 s, the string vibrates through half a cycle. Therefore, the period T is T = 0.050 s The frequency of the wave is f = 1 / T = 20 Hz For a standing wave, the distance between adjacent nodes
or between adjacent antinodes is
The speed of the wave is The number of half-wavelengths fitting into the length of the string determines the mode number N. Therefore, the 10th harmonic is excited.
The fundamental frequency f1 is
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