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6 ELECTROMAGNETISM

P60 007

An electron travels at 2.0´10⁷ m.s^-1 in a plane perpendicular to a 0.0100 T magnetic field.

(A1) Describe the path of the electron.

(A2) Calculate the radius of the circular orbit.

(A3) Calculate the period of motion.

(A4) Calculate the frequency of the electron.

View solution below only after you have completed the answering the question.

Solution

Centripetal force F_C = m v² / R

right hand palm rule Þ electron travels in a circular orbit

v = 2.0´10⁷ m.s^-1 |q| = 1.602´10^-19 C m = 9.11´10^-31 kg B = 0.010 T

R = ? m T = ? s f = ? Hz

Magnetic force = centripetal force