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6     ELECTROMAGNETISM

P60 008

The diagram shows two parallel horizontal metal plates connected to a battery. Suspended between the plates is a charged particle of mass 9.6´10-6 kg.

 

(A)      Using conventional symbols, draw the electric field between the metal plates.

(B)      Determine the magnitude of the electric field between the plates.

(C)      Determine the sign and magnitude of the charge on the particle if it is suspended motionless between the plates.

 

 

 

 

 

 

View solution below only after you have completed the answering the question.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Solution

m = 9.6´10-6  kg     V = 49 V    d = 20 mm = 20´10-3 m    E = ? V.m-1     q = ? C

uniform electric field 

electric force (up) = gravitational force (down)      charge must be positive