VISUAL PHYSICS ONLINE 7.1 THE NATURE OF LIGHT
ELECTROMAGNEITC WAVES P71 006 A student conducts an experiment using a photoelectric cell.
Light is shone through a grid onto a metal surface. The metal is at earth
potential and the grid is at 100 V, so that any electrons emitted from the
surface produce a current in the external circuit. The student shines light
sources of different photon energies onto the metal surface and records the
current flowing for each. The light sources are adjusted so that their
intensities are equal. The results are recorded in the table. Photon energy (eV) Photo-current
(μA)
0.5
0
0.9
0
1.2
0.5
1.70
2.8
1.75
4.0
1.90
8.0
2.20
9.2
2.50
9.4 (A) Plot the graph (X-axis – photon energy). (B) Draw the straight line of best fit in the region where the photo-current varies greatest with photon energy. (C) From the line drawn on your graph,
estimate the minimum energy (work function) for photoelectric emission. What
wavelength for the incident em radiation does this
correspond to and what part of the em spectrum? (D) The experiment is repeated, but the
intensities of the light sources are doubled. Predict the results of this new
experiment by drawing a second line on the graph. (E) Explain the shape of the curves. View solution below only after you have completed the answering the question. |
Solution
(D) Work function W = 1.6 eV lc = ? m W = 1.6 eV = (1.6) qe J qe = 1.602´10-19 C c = 3.0´ m.s-1 W = h fc = h c /lc = 2.563´10-19 C l = h c / W = 7.8´10-7 m = 780 nm infrared (E) For photon energy less than the threshold frequency, no electrons are released from the surface irrespective of the intensity. For energies above the threshold, as the energy is increased the number of electrons released increases as shown by the increase in the current – the greater the intensity more photons – more electrons released à greater current. When the energy becomes sufficiently high, almost all the available electrons are released from the surface and there is only a very small increase in current for increased energy of the photons– saturation effect. |