VISUAL PHYSICS ONLINE 8.1 FROM THE UNIVERSE TO THE ATOM
THE ATOM P81 009 In a modern cathode ray tube (CRO), the electrons are produced by thermionic emission from a hot filament forming the cathode. The heating of the filament by a low voltage DC power source causes electrons to be released from the hot filament with nearly zero kinetic energy. The electrons are then accelerated away from the filament by a large potential difference applied between the accelerating voltage plates. This forms a narrow electron beam with the electrons traveling at the same speed and impact onto the fluorescent screen to produce a bright spot in the centre. The accelerating voltage was 5.00 kV. When a magnetic field was applied perpendicularly to the electron beam, the electrons (cathode rays) followed a circular path with a radius of 5.57 mm. Calculate the strength of the magnetic field. View solution below only after you have completed the answering the question. |
Solution Accelerating voltages increases KE of electrons
Electron in a uniform magnetic field experiences a magnetic force that is always directed towards the centre of a circle – centripetal force
qe = 1.602´10-19
C me = 9.109´10-31 kg V = 5.00 kV = 5.00´103
V R
= 557 mm = 5.57´10-3 m B = ? T B = 0.043 T |