VISUAL PHYSICS ONLINE

MODULE 5

ADVANCED MECHANICS

MOTION OF SATELLITES

 

A satellite is an object that orbits a much more massive object. Natural satellites include the planets orbiting the Sun, the moons of Jupiter, and the Moon about the Earth.

 

 

An artificial satellite is an object put into orbit from the Earths surface using a spacecraft such a rocket or a space shuttle. Satellites are used for many applications and include military and civilian Earth observation satellites, communications satellites, navigation satellites, weather satellites, and research satellites. Space stations and human spacecraft in orbit are also satellites.

 

Satellites are placed in one of several different types of orbit depending on the nature of their mission. Two common orbit types are a Low Earth Orbit (LEO) and a Geostationary Orbit (GEO).

 

Low Earth Orbit (LEO) occur at a radius of between 200 and 2000 km above the Earths surface with periods varying from 60 to 90 minutes. The space shuttle uses this type of orbit (200-250 km). LEOs have the smallest field of view and frequent coverage of specific or varied locations on the Earths surface. Orbits less than 400 km are difficult to maintain due to atmospheric drag and subsequent orbital decay. They are used mainly for military applications, Earth observation, weather monitoring and shuttle missions. Except for the lunar flights of the Apollo program, all human spaceflights have taken place in LEO. The altitude record for a human spaceflight in LEO was Gemini 11 with an apogee of 1,374 km. All manned space stations and most artificial satellites, have been in LEO.

 

Orbital decay is the reduction in the height of an object's orbit over time due to the drag of the atmosphere on the object. All satellites in low Earth orbits are subject to some degree of atmospheric drag that will eventually decay their orbit and limit their lifetimes. Even at 1000 km, as thin as the atmosphere is, it is still sufficiently dense to slow the satellite down gradually.

 

A Geostationary Orbit (GEO) is a circular orbit in the Earth's equatorial plane, any point on which revolves about the Earth in the same direction and with the same period as the Earth's rotation. Geostationary orbits are useful because they cause a satellite to appear stationary with respect to a fixed point on the rotating Earth. As a result, an antenna can point in a fixed direction and maintain a link with the satellite. The satellite orbits in the direction of the Earth's rotation, at an altitude of approximately 35,786 km above ground. This altitude is significant because it produces an orbital period equal to the Earth's period of rotation, known as the sidereal day. These orbits allow for the tracking of stationary points on Earth and have the largest field of view. Applications include communications, mass-media and weather monitoring.

 

Web investigation artificial satellite orbits

http://en.wikipedia.org/wiki/Satellite

http://en.wikipedia.org/wiki/Low_Earth_orbit

http://en.wikipedia.org/wiki/Geostationary_orbit

 

CIRCULAR ORBITAL MOTION

We will assume that a satellite moves in a circular path around the Earth. To place an object into a stable Earth orbit at a given radius, the launch must give it both an initial vertical and horizontal component of velocity, relative to the Earths surface. The rocket will eventually turn so that it is travelling horizontal to the Earths surface. At this radius, the force of gravity provides the acceleration needed to keep the object moving in a circle, but a particular orbital velocity is also required to keep the object in a stable orbit (figure 2). To calculate that velocity, known as the orbital velocity , we equate expressions for centripetal force and gravitational force as follows:

centripetal force

Gravitational force

 

Orbital velocity of a satellite around orbiting the Earth in a circular path

(1) circular orbit

Note that the velocity of a satellite as it orbits around the Earth in a circle only depends on:

       Mass of the Earth

       Radius of the orbit

 

It is clear from this formula that altitude is the only variable that determines the orbital velocity required for a specific orbit. Further, the greater the radius of that orbit, the lower that orbital velocity .

 

The orbital velocity of a satellite around other planets is simply

(4) orbital velocity about any planet

The orbital motion of the Moon about the Earth

We can calculate the orbital velocity of the Moon orbiting the Earth using the equation 3 for the orbital velocity or knowing the period T of rotation of the Moon around the Earth is 27.3217 days.

 

The Moons orbital velocity of was calculated to be 1.02 km.s-1. The Moons orbit is not quite circular and the speed is only approximately constant. The orbital speed of the of the Moon varies from 0.970 to 1.022 km.s-1. So, our simple models gave numerical results which compare very favourably with the measured values for the orbital speed of the Moon.

 

 

 

ENERGY CONSIDERATIONS

Consider a satellite of mass m orbiting a massive object of mass

M (m << M assume M stationary w.r.t m) with an average orbital radius r, orbital speed and period T.

 

The net force acting on the satellite is the gravitational force

 

The gravitational force is responsible for the orbit, thus the gravitational force corresponds to the centripetal force

 

Hence the average orbital speed is

circular orbit

The gravitational potential of the satellite system is

and its kinetic energy is

circular orbit

The total energy of the system is

circular orbit

Conservation of energy

For a satellite in a circular orbit, the radius of orbit and the orbital velocity (tangential) are both constants. In an elliptical orbit, both the radius and orbital velocity change during the orbit of the satellite. However, the angular momentum L of the satellite remains constant

 

So, if the radius increases, the orbital velocity decreases or if the radius decreases, then the orbital velocity increases. By carefully examining figure 5, you will observe that when the satellite is at the aphelion position, the satellite is at the greatest distance from the massive object and its speed is a minimum. When the satellite is at the perihelion position, the position closest to the massive object and smallest radius, the speed is a maximum.

 

 

Exercise 1

A satellite of mass 2500 kg is in a low orbit trajectory at an altitude of 1000 km above the Earths surface. The satellite must be moved to a higher trajectory with an altitude of 2000 m.

Calculate for both orbits: the acceleration due to gravity (gravitational field strength), orbital speeds, periods, kinetic energies, gravitational potential energies and total energies.

How can this be achieved?

What energy must be used to shift the satellite into the higher orbit?

 

Solution

Problem: type / visualize / how to approach ? / scientific annotated diagram / what do you know ?

Acceleration due to gravity (gravitational field strength)

Orbit #1 g = 7.33 m.s-2

Orbit #2 g = 5.69 m.s-2

Orbital velocity decreases with increasing altitude.

The period of the satellite orbits

Orbit #1 T = 6.30x103 s = 1.75 h

Orbit #2 = 7.62x103 s = 2.12 h

Period increases with increasing altitude.

Kinetic energies of the satellite

Orbit #1 = 6.76x1010 J

Orbit #2 = 5.95x1010 J

KE decreases with increasing altitude.

Gravitational potential energies of the satellite

Orbit #1 = - 1.35x1011 J

Orbit #2 = - 1.19x1011 J

GPE increases with increasing altitude.

Total energies of the satellite

Orbit #1 = - 6.76x1010 J

Orbit #2 = - 5.95x1010 J

total energy increases with increasing altitude.

The total energy being negative means that the satellite is bound to the Earth.

 

The energy (work) required to move the satellite from orbit #1 to orbit #2 is the difference in the total energies between the two orbits

work W = E2 E1 = ( - 5.95x1010 + 6.76x1010 ) J

W = 0.81x1010 J

This energy for the work required to shift the orbit must come from the fuel that is burnt by the satellites rockets.

 

 

 

Exercise 2

How can we determine the mass of the Sun if we know the distance between the Sun and the Earth?

 

Solution

We can use Keplers 3rd Law

G = 6.67x10-11 N.m2.kg-2

T = TE = 1 y = (1)(365)(24)(3600) s = 3.17x107 s

r = RSE = 1.50x1011 m

 

Exercise 3 Gravitational Force on the Moon

The Moon, the Sun and the Earth are aligned so that both the Sun and the Earth are at right angles to each other. Find the net force acting on the Moon.

Solution

THINK: how to approach the problem (ISEE) / type of problem / visualize the physical situation / annotated scientific diagram / what do I know!

Need to calculate the forces between the Moon and Earth and between Moon and Sun and then add the two forces as vectors.

 

 

 

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Ian Cooper School of Physics University of Sydney

If you have any feedback, comments, suggestions or corrections please email Ian Cooper

ian.cooper@sydney.edu.au